A rectangular garden must have a perimeter of 160 feet and an area of at least 1300 square feet. Describe the possible lengths of the garden. Round your answers to the nearest foot.

PLEASE HELP

The lengths of the garden are 57.32 feet and 22.68 feet (approximately)

Step-by-step explanation: The area has been given as 1300 which means,

Area = L x W

1300 = L x W ———(1)

Also the perimeter has been given as 160, hence we also have

Perimeter = 2(L + W)

160 = 2(L + W)

80 = L + W ———(2)

From equation (2), make L the subject of the equation

L = 80 - W

Substitute for the value of L into equation (1)

1300 = L x W

1300 = (80 - W) x W

1300 = 80W - W^2

Rearranging the equation we now have;

W^2 - 80W + 1300 = 0

Since we cannot factorize we shall apply the quadratic equation formula to solve for W. Please refer to the attachment for details of this.

Having calculated the value of W to be either 57.32 or 22.68, we can now find the value of L as follows;

Substitute for the value of W into equation (1)

1300 = L x W

1300 = L x 57.32

Divide both sides of the equation by 57.32

22.68 = L.

(Note that if we take the other value of W which is 22.68, the value of L shall be 57.32)

Since the area of the rectangular garden must be AT LEAST 1300 square feet we shall use the exact values for;

Length = 57.32 feet

Width = 22.68 feet

d) the triangle is a right triangle 60 squared +144 squared= 156 squared

step-by-step explanation:

156 squared is the hypothenuse

so 156= c

(sin 42)/31. = sinx)/37

sinx = 37 (sin42)/31

= 37× 0.66/31 = 0.787

x= 51.9

other angle opposite to y = 180-51.9-42

= 180- 93.9 =86.1

so

sin42)/31 = sin 86.1)/y

0.021 = 0.997 /y

y= 0.997/0.021 =47.47