x^2 + 14x + 24
x(x^2/2+2x/x)+2^2 · 3 (2^2·3x/2^2·3+2^3·3/2^2·3)
(x - 9)(x + 5)
x² − 4x − 45 =
= x² + 5x - 9x - 45
= x(x + 5) - 9(x + 5)
= (x - 9)(x + 5)
To factor an equation, break the polynomial into two binomials which multiply to make it. There are three main ways to factor:
Regular: Find two numbers that multiply to C and add to B from .
Grouping: Find two numbers that multiply to A*C and add to B. Then split B into the two factors and factor by GCF.
Difference of Squares: Factor by taking the square root of each term.
Ask yourself; Which two numbers add up to 4 and multiply to -5?
-1 and 5 do
Now rewrite the expression using what you have above
(x - 1)(x + 5)
The answer to your question is: ( x + 6 ) ( x - 2 )
Factor x² + 4x - 12 = 0
Find two numbers that added gives +4 and if we multiply them get -12
We can find these numbers by decomposing -12 in its prime factors
6 2 12 = 2 x 2 x 3
3 3 now combine the numbers to get -12 and + 4
1 2 and 2 x 3 = 6
and 2 x 6 = 12
( x + 6 ) ( x - 2 )
x2 + 4x - 21
Okay, here's what you have to do.
It's a two termed expression because it's x squared.
So, start your problem off like this.
(x ) (x )
The middle, 4x, and the 21 go together, in a way.
You have to find two numbers that multiplied make 21,
but at the same time can subract to make 4.
(The only reason it's subtract to make 4 in this problem
is because of the minus sign in front of the 21. That sign
will tell you whether the two numbers should add or
subract to give you the middle number.)
You're numbers in this case are 7 and 3.
7 times 3 equals 21.
7 minus 3 equals 4.
I don't exactly remember all the rules with the signs,
but I believe it should look like this:
I wouldn't swear on it because it's been awhile,
but I think that's right.
Hope it helped!
x^2 + 14x + 24 =...