X-2y= -4 and y= -x + 2 solve the system of equations

(0, 2 )

Step-by-step explanation:

Given the 2 equations

x - 2y = - 4 → (1)

y = - x + 2 → (2)

Substitute y = - x + 2 into (1)

x = - 2(- x + 2) = - 4 ← distribute and simplify left side

x + 2x - 4 = - 4

3x - 4 = - 4 ( add 4 to both sides )

3x = 0 ⇒ x = 0

Substitute x = 0 into (2)

y = 0 + 2 = 2

Solution is (0, 2 )

a4 - 3a2 - 1

step-by-step explanation:

step   1   :

equation at the end of step   1   :

  ((a4) -   3a2) -   1

step   2   :

trying to factor by splitting the middle term

2.1     factoring   a4-3a2-1  

the first term is,   a4   its coefficient is   1 .

the middle term is,   -3a2   its coefficient is   -3 .

the last term, "the constant", is   -1  

step-by-step explanation: