Given the following use a Pythagorean identity to find tan(0) if 0 is in quadrant IV

A. -3√7/7

Step-by-step explanation:

We have the equation in trigonometry as following:

with (cos x)^2 different from 0, we have:

=>

As (cos θ) = √7/4 ≠ 0, so that we can replace  θ into the above equation, we could have:

(tan θ)^2 = 1/[(cos θ)^2] -1

=> (tan θ)^2 =

=>(tan θ)^2 = 16/7 - 7/7 = 9/7

=> tan  θ = (3√7)/7

or tan  θ = - (3√7)/7

As θ is in quadrant IV, so that its tangent has negative value

=> tan θ =  -3√7/7

So that the correct answer is A

36/60

36/2=18

60/2=30

18/30

18/3=6

30/3=10

6/10

6/2=3

10/2=5

your final answer would be 3/5 of an

hope this !

3 is greater then both of those numbers