The vagabonds were 200 miles apart at 2 p. M and were headed toward each other if they met at 6 p. M and one was traveling 10 miles per hour faster than the other what was the speed of each vagabond

First vagabond: 30 miles per hour

Second vagabond: 20 miles per hour

Step-by-step explanation:

Let's call the speed of the first vagabond A, and the speed of the second vagabond B.

They were heading toward each other, so the relative speed is the sum of both speeds: A+B

The total number of hours spent until they meet is 6 - 2 = 4 hours, so we have the first equation:

(A+B) * 4 = 200

A + B = 50

One vagabond was traveling 10 miles faster than the other, so we have the second equation:

A = B + 10

Using the value of A from the second equation in the first one, we have:

B + 10 + B = 50

2B = 40

B = 20 miles per hour

Now, from the second equation, we find the value of A:

A = 20 + 10 = 30 miles per hour

answer:   28.56 feet (approx)

step-by-step explanation:

since, triangle abc has measure of angle c equal to 55 degrees, measure of angle abc equal to 90 degrees, and length of bc equal to 20 feet.

we have to find out the measurement of segment ab.

therefore, tan 55° =

but bc = 20 feet.

⇒ tan 55 ° =  

⇒ ab = 20 × tan 55 °

⇒ ab = 20 × 1.42814800674

⇒ ab = 28.5629601348   ≈ 28.56 feet

2(2x + 3) = -4 + 2(2x + 5)

4x + 6 = -4 + 4x + 10

4x + 6 = 4x + 6

4x - 6 + 6 = 4x - 6 + 6

4x = 4x

x = x

unlimited solutions.