Are 16% of M&M’s Green? Mars, Inc. claims that 16% of its M&M plain candies are green. A sample of 100 M&Ms is randomly selected. a. Find the mean and standard deviation for the numbers of green M&Ms in such groups of 100. b. Data Set 18 in Appendix B consists of a random sample of 100 M&Ms in which 19 are green. Is this result unusual? Does it seem that the claimed rate of 16% is wrong?

This result is not unusual.

So, it does not seem that the claimed rate of 16% is  wrong

Step-by-step explanation:

Since we have given that

n = 100

p = 0.16

q = 1 - 0.16 = 0.84

So, Mean would be

and standard deviation would be

Now, if there are 19 green,

so, we will check how it is far,

Since it is 0.817 standard deviations away from the mean.

So, this result is not unusual.

So, it does not seem that the claimed rate of 16% is  wrong.

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step-by-step explanation:

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