6. Bons grocer wishes to mix some nuts worth 90 cents per pound with some nuts worth $1.60 per pound to make 175 pounds of a mixture that is worth $1.30 per pound. How much of each should she use? Include your equation. *

75 pounds and 100 pounds.

Step-by-step explanation:

Given:

Bons grocer wishes to mix some nuts worth 90 cents( $0.9) per pound with some nuts worth $1.60 per pound to make 175 pounds of a mixture that is worth $1.30 per pound.

Question asked:

How much of each should she use?

Solution:

Let there are two types of nuts mixed in the mixture, one is nut A and another is nut B.

As we know:

1 cent = $0.01

90 cents = $0.01 90 = $0.9

Let quantity of nut A mixed =

Quantity of nut B mixed =

Total quantity of mixture = 175 pounds

Total cost of mixture = Cost per pound Total quantity of mixture in pound

                                  = $1.30 175 = $227.5

As mixture is prepared by mixing two types of nuts:-

Cost per pound of nut A Quantity mixed + Cost per pound of nut B

By subtracting both sides by 280

Minus canceled by minus

Substituting the value:-

Quantity of nut A mixed = = 75 pounds

Quantity of nut B mixed = = 175 - 75 = 100 pounds

Therefore, Bons grocer wishes to mix 75 pounds of nuts worth 90 cents ($0.9) with 100 pounds of some nuts worth $1.60 per pound to make  175 pounds of a mixture that is worth $1.30 per pound.

t = 3

step-by-step explanation:

put t = 3 in this expression :

(3²-1)(3²-2)(3² - 3)(3² - 4) = 8×7×6×5 = 56×30 = 1680

it should be a and d. lmk if i'm wrong xd