What is the volume of the square pyramid with base edges 32 mm and slant height 34 mm?

9,920 mm3

10,010 mm3

7,680 mm3

10,240 mm3

The answer to your question is 10240 mm³

Step-by-step explanation:

Data

length of the base = 32 mm

length of the height = 34 mm

Formula

Volume of a pyramid = 1/3 x Area of the base x length of the height

Process

1.- Calculate the area of the base

Area = side x side

        = 32 x 32

        = 1024 mm²

2.- Find the height of the pyramid using the Pythagorean theorem

height² = 34² - 16²

height² = 1156 - 256

height² = 900

height = 30

3.- Calculate the volume of the pyramid

Volume = 1/3Area x height

             = 1/3(1024 x 30)

             = (30720)/3 mm³

             = 10240 mm³

b. an equilateral triangle inscribed in a circle

step-by-step explanation:

we are given the figure of two circles having a triangle inside.

now, we know that,

"when a figure is lying inside an another figure, then the outside figure is known as circumscribed figure and the figure lying inside is referred to as the inscribed figure".

as we see that, the circles are containing the triangle completely.

thus, the circles are the circumscribed figures and the triangle is the inscribed figure.

hence, we get, 'an equilateral triangle is inscribed in a circle'.