The lateral surface area of a right square pyramid is given by s - 82.492. If the pyramid has height 10 feet and lateral surface
area 100 square feet, what is the length of a side b of its base?
a. $6.92586 ft
C. 1.36523 ft
b. 4.85868 ft
d. 9.36369 ft

a is the answer.

Step-by-step explanation:

S- 82.492 = Perimeter base x height /2 + base

Pyramid base

b x 10h = hb /2  + b =  100

6.92586 x 6.92586  x 10 = 479.675367396/2 =239.837683698+ base 47.9675367396 =287.805220438

479.675367396- 287.805220438 = 191.870146958

Proving each rectangle pyramid side is 1/4 of 287.805220438/4 = 72 +10 height =S- 82    (S = 82.492)

then 192/2 = 96 = 100 square feet

answer: the two figures are congruent.

step-by-step explanation: they're congruent because figure efgh is reflected across the x and y axis but it was also rotated.

hope it !

ca = ec

cpctc makes it so that corresponding parts of the triangle you proved to be equal are equal, the other options aren't part of the part of the triangles you proved to be equal.