The length of a rectangle is 8 centimeters less than its width. What are the dimensions of the rectangle if its area is 180 square centimeters?
The length of the rectangle is___cm.
The width of the rectangle is___cm.

Step-by-step explanation:

hello :

let :

y : the length  , x : the width   , A : the area, x and y positifs numbers (y>x)

you have the system : xy=180(*)

                                    y=x+8...(**)

put the value for y by (**) in to(*) : (x+8)x=180

x²+8x-180 =0a=1   b=8    c = -180

∆ = b²- 4ac

∆ = 8²- 4(1)(-180)=384=28²

X1 = ( -b - √∆)/2a  = (-8-28)/2 = -15 refused

X2= ( -b + √∆)/2a  = (-8+28)/2 = 10

x=10   but : y=x+8

                 y = 10+8 =18

The length of the rectangle is...18...cm.

The width of the rectangle is...10...cm.

a. 19,958,400

step-by-step explanation:

hope this

intensity of the vector is v= √37 ≈ 6.08 units and make angle ∡α ≈ 9.46° with east direction

step-by-step explanation:

required vector is consists of the two componentsvx= 2+4=6 units   and vy= 1 unit and vx ⊥ vywe will use pythagorian theorem to find intensity of the vector vv∧2 = vx∧2 + vy∧2 => v = √vx∧2 + vy∧2 = √6∧2 + 1∧2 = √36+1 = √37 ≈ 6.08 unitsthe angle ∡α between vector and east direction we wil find with tanαtanα = 1/6 => α = arc tanα = arc 1/6 => α ≈ 9.46°

hope this