4r-3=3(3r+4) what is r

r=-3

Step-by-step explanation:

Step 1: Simplify both sides of the equation.

4r−3=3(3r+4)

4r+−3=(3)(3r)+(3)(4)(Distribute)

4r+−3=9r+12

4r−3=9r+12

Step 2: Subtract 9r from both sides.

4r−3−9r=9r+12−9r

−5r−3=12

Step 3: Add 3 to both sides.

−5r−3+3=12+3

−5r=15

Step 4: Divide both sides by -5.

−5r

−5

=

15

−5

Mark me brainliest if this helped :D

456567546657689765432567890-9876543567890-987657890

step-by-step explanation:

option a, c,d are correct.

step-by-step explanation:

from the given figure, it is given that z is equidistant from the sides of the triangle rst, then from triangle tzb and triangle szb, we have

tz=sz(given)

bz=zb(common)

therefore, by rhs rule,δtzb ≅δszb

by cpctc, sz≅tz

also, from δctz and δasz,

tz=sz(given)

∠tcz=∠saz(90°)

by rhs rule, δctz ≅ δasz, therefore by cpctc, ∠ctz≅∠asz

also,from δasz and δzsb,

zs=sz(common)

∠zbs=∠saz=90°

by rhs rule, δasz ≅δzsb, therefore, by cpctc, ∠asz≅∠zsb

hence, option a, c,d are correct.