Allen has four times as many cards as Bob, and Jane has twice as many cards as Allen. Together, Allen and Jane have 468 cards. How many cards do Allen, Jane, and Bob each have?

Let Allen be A , Jane be J and Bob be B

Allen has 4 times as Bob

So

A = 4B

Jane has twice as Allen

So

J = 2A

Together, Allen and Jane has 468 cards

A + J = 468

Substitute 2A for J in the third equation.

We have

A + J = 468

A + 2A = 468

3A = 468

Divide both sides by 3

3A/3 = 468/3

A = 156

Recall

A = 4B

Therefore

156 = 4B

Divide both sides by 4

156/4 = 4B/4

39 = B

B = 39

Also,

J = 2A

J =2 x 156

J = 312

Allen has 156 cards

Jane has 312 cards and

Bob has 39 cards

Step-by-step explanation:

the slope of the line is 60

one point on the line is (40,10)

step-by-step explanation:

in the equation outside the parenthesis the equation always tells you the slope. in this case it is 60.

in the parenthesis is also says 40 which is x because it is near the x and 10 is y because it is near y.

answer: approximately 206 bones

i hope this u out a branlist and a would be greatly appreciated :