A company hires management trainees for entry level sales positions. Past experience indicates that only 29% will still be employed at the end of nine months. Assume the company recently hired 9 trainees. Assuming independence, what is the probability that exactly five of the trainees will still be employed at the end of nine months?

0.0656 is the probability that exactly five of the trainees will still be employed at the end of nine months.

Step-by-step explanation:

We are given the following information:

We treat management trainees still employed at the end of nine months as a success.

P(Employed) = 29% = 0.29

Then the number of trainees follows a binomial distribution, where

where n is the total number of observations, x is the number of success, p is the probability of success.

Now, we are given n = 9

P(exactly five of the trainees will still be employed at the end of nine months)

We have to evaluate:

0.0656 is the probability that exactly five of the trainees will still be employed at the end of nine months.

14.3

step-by-step explanation:

add all the numbers together.

9 + 12 + 15 + 16 + 17 + 17 = 86

now, divide 86 by how many numbers we have: 6.

86 / 6 = 14.3

your answer is b.

x = 33.9

y = 65.6

step-by-step explanation: