A researcher randomly assigned N = 16 rodents to experience one of four levels of shock (n = 4 per group) following the illumination of a visual cue. If SSBG = 24 and SSE = 48, then what was the decision at a .05 level of significance for a one-way between-subjects ANOVA?

The hypothesis should be retained

Step-by-step explanation:

We are given:

N= 16

n = 4

Level of significance, a = 0.05

From the given data, our ANOVA table will be:

Note: proper ANOVA table is attached

The statistic will be written as:

T = 8/4 = 2

Therefore

The hypothesis should be retained, because we no know that the statistic is in the acceptance area.

you would need to know all the numbers that are on there

step-by-step explanation:

(0,-3) see attached graph

step-by-step explanation:

a. to solve the system, graph the two equations.

x = y+3 becomes y=x-3 has m=1/1 and b=-3. start at (0,-3) on the y-axis and plot a point. then move up 1 unit and 1 unit to the right. plot a point and connect.

y=-4x+3 has m =-4/1 and b=-3. start at (0,-3) on the y-axis and plot a point. then move down four units and to the right 1 unit. plot a point and connect.

the solution is the point (x,y) where the two lines intersect. by the graph below it is (0,-3).

b. to solve by substitution, substitute y = -4x-3 into x= y+3

x= (-4x-3) +3

x=-4x

5x=0

x=0

now substitute x = 0 back in to find y.

y= -4(0)-3

y=0-3

y=-3

solution is (0,-3)

c. use elimination by adding the equations together.

x-y=3

4x+y=-3

5x=0

x=0

then substitute into one equation to find y.

y=-4(0)-3

y=-3