Triangle uptop oneside is 57 the other side is 61 bottom left is x and bottom roght is 67

is it a right triangle (has a right angle)? if so, you just apply the Pythagorean Theorem. (skip to the bottom if you don't care)

a²+b²=c²

substitute A and B for the two lines (legs) that make up the right angle, and for C you will substitute the hypotenuse (longest line, slanted.)

once you do that, you take the two numbers you do have and simplify (get rid of the ².) then you use the 2 numbers to find the third.

this means you either

add the A and B together

A= 3²

B= 4²

C=?

3²+4²=C²

3² is 9

4² is 16

9+16=C²

25=C²

simplify

5=C

or you minus C by the number you do have.

A= 3²

B=?

C= 5²

3²+B²=4²

3² is 9

5² is 25

9+B²=25

minus both the 25 and the 9 by 9 to get rid of it.

9-9=0

25-9=16

this gets rid of the 9 on the left side by turning it into a 0.

that leaves

B²=16

you can either simplify further from here or leave it, depending on if the square root of C is a simple number.

in the case of 16, the square root is 4, which ends with no repeating decimals, so you should simplify.

something you should simplify

16² because it equals a simple number.

something you shouldn't.

13² because it equals an ongoing decimal.

(bottom)

if you still need help and can't do it yourself, or if you don't want to do it, then comment, I can continue to help. I just need to know if it's a right triangle or not. the way I solve the question depends on the type of triangle it is.

congruent segments

step-by-step explanation:

a

step-by-step explanation: