Find the arc length of the following curve on the given interval. x equals 8 t minus 7 comma y equals 15 t minus 6x=8t−7, y=15t−6, 0 less than or equals t less than or equals 40≤t≤4 The length of the curve is nothing. (Type an integer or a fraction.)

  612

Step-by-step explanation:

Both x and y are linear functions of t, so for each increment of t, the x- and y-coordinates will increment by 8 and 15, respectively. The length of a line segment joining points 8 units in the horizontal direction and 15 units in the vertical direction is given by the Pythagorean theorem as ...

  d = √(8² +15²) = 17

From t=4 to t=40, there are 36 increments in t, so the length of the line segment defined by the given functions is ...

  36×17 = 612 . . . units

step-by-step explanation:

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step-by-step explanation:

the options are kind of confusing. i can tell you what i see going on here when i look at the graph.

the class and exam medians are closely related, and it looks like the low outlier on the exam did pull the median lower. [tex][/tex]