The axis of symmetry for a function in the form f(x) = x2 + 4x − 5 is x = −2. what are the coordinates of the vertex of the graph?

(−9, −2)
(−17, −2)
(−2, −17)
(−2, −9)

The coordinate of the vertex of the graph is (₋2 , ₋9)

The quadratic function has the following general equation:

If x₁ and x₂ are the roots of a function of a quadratic equation, then:

Discriminant of quadratic equation ( ax² + bx + c = 0 ) could be calculated by using:

From the value of Discriminant , we know how many solutions the equation has by condition:

Let us tackle the problem.

The coordinate of the vertex of quadratic function ax² + bx + c can be calculated using the following formula :

If the given function is f(x) = x² + 4x − 5 , then :

Coordinate of the Vertex =

Coordinate of the Vertex =

Coordinate of the Vertex =

Grade: College

Subject: Mathematics

Chapter: Quadratic Equations

Keywords: Equation , Line , Variable , Line , Gradient , Point , Quadratic , Intersection

step-by-step explanation:

through just a quick inspection, one can see that the graph of this cubing function starts in quadrant iii and ends in quadrant i.   when x = 0, y = 3, so the y-intercept is (0, 3).

if graphs are part of the problem statement, share them.   .

560

step-by-step explanation:

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