A point is chosen at random on the coordinate plane such that both of its coordinates are between 0 and 2. What is the probability that the point is less than 1 unit from the origin?

pi/16

Step-by-step explanation:

draw a 2 by 2 grid to choose a point.

The grid's area is 4, right? Draw a quarter of a circle in the graph.

Any point less than one on there is going to be your answers.

The area of the circle is pi/4. But we want less than 1 not 2.

So we divide by four again to get pi/16.

Hope this helps :)

the direct variation says that:

then the equation is of the form is given by:

            where k is the constant variation.

from the given table:

consider any value of x and m(x)=y

x = 2 and m(x)=y = 3

substitute these value in [1]; we have;

divide both sides by 2 we get;

⇒

check:

put x = -1 and m(x) = -1.5

substitute in the equation:

-1.5 = -1.5                   true

therefore, the function m(x) represents a direct variation

graph of this function as shown below:

the answer is c

hope this !