The number of times per minute that a hummingbird's wings flap is normally distributed with a mean of 145 and a standard deviation of 2. Part A: What is the probability that a randomly selected hummingbird flaps its wings more than 151 times a minute? Part B: What percentage of hummingbirds flap their wings between 141 and 149 times per minute? Part C: A hummingbird that flaps its wings 147 times a minute is in the percentile.

a) 0.0013

b) 0.9544

c) 84.13 percentile.

Step-by-step explanation:

We are given the following information in the question:

Mean, μ = 145

Standard Deviation, σ = 2

We are given that the distribution of wings flap is a bell shaped distribution that is a normal distribution.

Formula:

a) P( flaps its wings more than 151 times a minute)

Calculation the value from standard normal z table, we have,  

b) P( flap their wings between 141 and 149 times per minute)

c) Percentile of  hummingbird that flaps its wings 147 times a minute

Calculation the value from standard normal z table, we have,  

Thus, A hummingbird that flaps its wings 147 times a minute is in the 84.13 percentile.

hello :

70y^8 + 30y^6 = 2 ( 35 y^8 + 15y^6)

the lenght is : 35 y^8

the width is : 15y^6

$9.41

step-by-step explanation: