Huma hubna and seema recieved a total of rs 2016 as monthly allowance from their mother such that seema gets 1/2 og what huma gets and hubna gets 1 2/3 times seemas share how much do the three sisters get individually

huma's share= Rs.864

Seema's share= Rs.432

Hubna's share= Rs.720

Step-by-step explanation:

Considering 'x' as the share of huma

Therefore , Seema's share will be x/2

And Hubna's share will be 5/3 * x/2 => 5x/6

Total money given in the problem is Rs.2016

In order to find the share of individual, we first have to determine 'x' variable by taking the sum of all shares.

x+x/2+5x/6=Rs.2016

(6x+3x+5x)/6=2016

14x/6=2016

x=2016 * 6/14

x=864.

Therefore,huma's share 'x' will be Rs.864

Seema's share will be = x/2 = Rs.432

And Hubna's share will be = 5x/6= Rs.720

3.how is solving radical equations different than solving linear equations?

step-by-step explanation: