Find the product of
(3y2 + 2y + 2)(3y2 – 4y – 5)

= 9y^4 -6y^3 -17y^2 -18y -10

Step-by-step explanation:

(3y^2 + 2y + 2) x (3y^2 – 4y – 5)

9y^4 - 12y^3 - 15y^2 + 6y^3 -8y^2 -10y +6y^2 -8y -10

= 9y^4 -6y^3 -17y^2 -18y -10

the answer to the question is a

step-by-step explanation:

it has the same slope and the same y-intercept.

y + 11 = -7/9(x - 18)

y + 11 =-7/9x + 14

b

y = -7/9x + 3

y-intercept (0, 3)