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Mathematics, 21.04.2020 02:05 dora8798
We are given AB ∥ DE. Because the lines are parallel and segment CB crosses both lines, we can consider segment CB a transversal of the parallel lines. Angles CED and CBA are corresponding angles of transversal CB and are therefore congruent, so ∠CED ≅ ∠CBA. We can state ∠C ≅ ∠C using the reflexive property. Therefore, △ACB ~ △DCE by the
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We are given AB ∥ DE. Because the lines are parallel and segment CB crosses both lines, we can consi...
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