Use the given conditions to write an equation for the line in point-slope form and in slope-intercept form.
Passing through (7,1) with x-intercept -5
Write an equation for the line in point-slope form...
WILL GIVE BRAINLIEST!!!

Step-by-step explanation:

Point-slope form is: , where (x_1, y_1) is the point given and m is the slope.

The problem gives us two points, actually: (7, 1) and (-5, 0); the second one is the x-intercept because x-intercepts always have a y-coordinates of 0. We can use these two points to find the slope, which is just change in y over change in x: . So, the slope = m = 1/12.

Now, we have our point (7, 1) and the slope 1/12, so just plug these into the above format:

Hope this helps!

y - 1 = (1/12)(x - 7)

y = (1/12)(x + 5)

You can use either of these

Step-by-step explanation:

Slope using (-5,0) and (7,1)

m = (0-1)/(-5-7) = -1/-12

m = 1/12

y - 1 = (1/12)(x - 7)

Or,

y - 0 = (1/12)(x - -5)

y = (1/12)(x + 5)

560

step-by-step explanation:

giggidy

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