The length of a basketball court is twice its
width. The perimeter is 150 feet. Find the
length and width of the basketball court.

Given:

The length of a basketball court is twice its  width.

The perimeter of the perimeter is 150 feet.

To find the length and width of the basketball court.

Formula

The perimeter of the rectangle is

where, l be the length of the rectangle and

b be the width of the rectangle.

Now,

As per the problem,

Let, the width be , so the length be

So,

The perimeter is =

According to the problem,

Therefore,

the width of the court is 25 ft and length = 2×25 = 50 ft

Hence,

The length and width of the basketball court is 50 ft and 25 ft respectively.

13

step-by-step explanation:

distance formula is d=√(x2-x1)^2   +   (y2-y1)^2

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step-by-step explanation: