You have some tigers. You have some cages. If you put one tiger in each cage, your will have one tiger left over. If you put two tigers in each cage, you will have one cage left over. How many tigers do you have? How many cages do you have?

The correct answer is there are 3 cages and 4 tigers.

Step-by-step explanation:

Let there be x cages and y tigers.

According to the first condition, if we put one tiger in each cage, one tiger is left over.

∴ y - x =1

According to the second condition, if we put two tigers in each cage, one cage is left over.

∴ x - =1

⇒ 2x - y = 2

Therefore adding both the equations we get,

y - x + 2x - y = 2 + 1

⇒ x = 3

⇒ y = 4

Therefore there are 4 tigers and 3 cages.

image result for what is another name for consecutive interior angles? ​

when two lines are crossed by another line (called the transversal): the pairs of angles on one side of the transversal but inside the two lines are called consecutive interior angles. in this example, these are consecutive interior angles: d and f.

step-by-step explanation: