A store sells televisions for $360 and video cassette recorders for $270. At the beginning of the week its entire stock is worth $56,430. During the week it sells three quarters of the televisions and one third of the video cassette recorders for a total of $32,310. How many televisions and video cassette recorders did it have in its stock at the beginning of the week

The number of Television at the beginning was 90

The number of video cassette recorders at the beginning was 89

Step-by-step explanation:

Selling Price of 1 Television =$360.

Selling Price of 1 video cassette recorders for $270.

Let the number of Television at the beginning=x

Let the number of video cassette recorders at the beginning =y

Opening Stock =$56,430.

Therefore:

It sells three quarters of the televisions and one third of the video cassette recorders for a total of $32,310.

270x+90y=32310

We then solve the two equations to obtain x and y.

97200x+72900y=15236100

97200x+32400y=11631600

Subtract

40500y=3604500

y=89

Substitute y=89 into 270x+90y=32310 to obtain x

270x+90(89)=32310

270x=32310-8010=24300

x=90

Therefore:

The number of Television at the beginning was 90

The number of video cassette recorders at the beginning was 89

where is abdul's work? don't see that anywhere posted : /

step-by-step explanation:

step-by-step explanation:

for exempl this   system of equations   y = x - 3

                                                                y = 2x - 5

look   the line : y = x -3     ( red)

                            the line : y = 2x -5 ( bleus)