How does the value of log 100 compare with the value of log 20?
The value of log 100 is about 4 times the value of loge 20
The value of log2100 is about 7 times the value of loge 20
The value of log2100 is about 3 times the value of log 20
O
The value of log2100 is about 3 times the value of loge 20

option A

Step-by-step explanation:

log_2(100)

we can simplify it

we can use base change formula

log_2 (100)=\frac{ln\left(100\right)}{ln\left(2\right)}

log_2 (100)=6.643856

Second value is :

log_6(20)

we can simplify it

we can use base change formula

log_6(20)=\frac{ln\left(20\right)}{ln\left(6\right)}

log_6(20)=1.67195

so, we know that

6.6438 is almost 4 times of 1.67195

step-by-step explanation:

we can use this expression to calculate the energy gain as a particle moves with a field or the energy loss as it moves against it. (note that it is also used to define the electron-volt, a unit of energy equal to that gained by an electron as it falls through a pd of 1 v, i.e. w = 1 ev = 1.6 10-19 c 1 v = 1.6 10-19j).in fact this expression is really nothing more than the statement that potential is the potential energy per unit charge. in this case, v= w/qis simply stating that the change in potential energy(or work done) per unit charge is equal to the change in potential (or potential difference), v.student questions: uniform electric fields2electron beamcathode+5 kvanode0 v

i'm sorry mate, but i am not seeing any figures. i am unable to solve this for you.