Write the equation of a line in slope-intercept form that is parallel to the given line and passes through the point (12,-25).

y= 1/4x+2

And then since the new equation have the following form:

We can use the point given (x=12, y = -25) in order to find the intercept with this equation:

And solving for the intercept b we got:

We subtract in both sides 3 and we got:

And our final equation who satisfy the condition given is:

Step-by-step explanation:

For this case we have the following equation given:

And we want to find an equation of a line parallel to the given function and this case we need to satisfy this condition:

And then since the new equation have the following form:

We can use the point given (x=12, y = -25) in order to find the intercept with this equation:

And solving for the intercept b we got:

We subtract in both sides 3 and we got:

And our final equation who satisfy the condition given is:

the line of

(b) 240

step-by-step explanation:

first, we use the pythagorean formula using the given side lengths to find x. then we use x to find the side lengths. then we add the side lengths to find the perimeter.

pythagorean theorem formula:

a^2 + b^2 = c^2

(x - 20)^2 + (x - 40)^2 = x^2

x^2 - 40x + 400 + x^2 - 80x + 1600 = x^2

x^2 -120x + 2000 = 0

(x - 100)(x - 20) = 0

x - 100 = 0 or x - 20 = 0

x = 100 or x = 20

we see that the solution x = 20 must be discarded because it will give a negative side length and a side length of 0. the only valid solution is x = 100.

perimeter = sum of the lengths of the sides

perimeter = x + x - 20 + x - 40

perimeter = 3x - 60

replace x with 100.

perimeter = 3(100) - 60

perimeter = 300 - 60

perimeter = 240