Evaluate this expression: 39:02
+ 1)-2 x(4+1).

Refer to the table below if needed. second quadrant third quadrant fourth quadrant sin(1800- - cos(180° -) tan(180°-e) =- tane cot(1800-0) 10 it to solo 888 sin(180° +c) = - sine cos(180° +) =- cose tan(180° +c) = tane cot(180° +o) = cote sec(180° + c) = - seco csc(180° +2) = - csce sin(360° -) =- sine cos(360° -) = cose tan(360° - e) =- tane cot(360° -) = -cote sec(360° -) = seco csc(360° -) = csco sec(180° -) = csc(180° -) = csca 1991 given that sine = 3/5 and lies in quadrant ii, find the following value. tane

If you apply the changes below to the absolute value parent function, f(x)=\x\, which of these is the equation of the new function? shift 2 units to the left shift 3 units down a. g(x)=\x-3\-2 b. g(x)= \x-2\-3 c. g(x)= \x+3\-2 d. g(x)= \x+2\-3

Iwill give ! if m∠a=59 and m∠3=81°, what is m∠b? m∠b= _[blank]_°