Use the counting techniques from the last chapter. A bag contains three red marbles, four green ones, one fluorescent pink one, two yellow ones, and four orange ones. Suzan grabs four at random. Find the probability of the indicated event. She gets all the red ones, given that she gets the fluorescent pink one.

The probability that she gets all the red ones, given that she gets the fluorescent pink one, is P=0.0035 or 0.35%.

Step-by-step explanation:

Susan grabs four marbles at random.

We have to calculate the probabilities that he picks the 3 red ones, given that she already picked the fluorescent pink.

If it is given that the fluorescent pink is already picked, we are left with three red marbles, four green ones, two yellow ones, and four orange ones. A total of 13 marbles.

The probability that the second marble is red is 3 in 13.

The probability that the third marble is also red is 2 (the red marbles that are left) in 12 (the total amount of marbles left), as there is a picking without replacement.

The probability that the fourth marble is 1 in 11.

Then, the probability that the 3 red marbles are picked, is:

the direct variation says that:

then the equation is of the form is given by:

            where k is the constant variation.

from the given table:

consider any value of x and m(x)=y

x = 2 and m(x)=y = 3

substitute these value in [1]; we have;

divide both sides by 2 we get;

⇒

check:

put x = -1 and m(x) = -1.5

substitute in the equation:

-1.5 = -1.5                   true

therefore, the function m(x) represents a direct variation

graph of this function as shown below: