My street hockey team plays three games each week. My team lost all $12$ games in the first four weeks. Then, my team won two games and lost one game in the fifth week, bringing our record to $2$ wins and $13$ losses. Each week after that, my team won two games and lost one game. My team first wins at least $60\%$ of its games by the end of $n$ weeks. What is $n$?

At the end of the 10 th week

Step-by-step explanation:

My team plays 3 games and lost all of them  (12 $ ) in the first 4 week

so in 4 weeks my team lost  12 $ and all the games  

Then total games in three weeks is   4 * 3  = 12

Total lost  12$  then we have a one dolar bet

In the 5th week my team wins 2$ ( two games ) and at the end of 5th week record is:

From 15 games  my team won  2  games  and lost  13 games and from that on, my team always wins 2 games then:

Let call x number of week after the 5th then

2 + 2*x / 15 + x  =  0,6                                0,6  =  60 %

Solving for  x

2 + 2*x  =  0,6 * ( 15 + x )

2 + 2*x  =  9  + 0,6 *x

2*x - 0,6*x  =  9 - 2

2*x - 0,6*x  = 7

1,4*x  = 7

x  =  7/1,4

x  =  5 weks later

Then the answer is 10 weeks

include a picture of the drawing in order for me to

step-by-step explanation:

step-by-step explanation:

the ratio of red paint to blue paint is always 9/7. that means that, whatever x's value, (4x+12)/(4x-4) has that same ratio. so, set up an equation and cross-multiply to solve for x:

9/7 = (4x+12)/(4x-4)

9(4x-4) = 7(4x+12)

36x - 36 = 28x + 84

8x - 36 = 84

8x = 120

x = 15