The population of a community was 200 people 10 yrs ago. Today the population is 550 people. Using an exponential growth function when will the population be 1000?

  in 6 years

Step-by-step explanation:

Using t=10 to represent today, we can write the exponential growth function as ...

  p(t) = 200(550/200)^(t/10)

Then we can set p(t) = 1000 and solve for t:

  1000 = 200(11/4)^(t/10) . . . . simplifying the growth factor

  1000/200 = (11/4)^(t/10) . . . . divide by 200

  log(5) = (t/10)log(11/4) . . . . . . take logs

  t = 10·log(5)/log(11/4) ≈ 15.91

That is, about 16 years from 10 years ago, the population will reach 1000.

The population will reach 1000 in about 6 years.

c) yes, because of asa or aas

you didn't post any answer choices, so its not 100% clear what your teacher is looking for

however, log(15/7) is equivalent to log(15) - log(7)

i'm using the rule log(x/y) = log(x) - log(y)