The times a fire department takes to arrive at the scene of an emergency are normally distributed with a mean of 6 minutes and a standard deviation of 1 minute. For about what percent of emergencies does the fire department arrive at the scene in between 4 minutes and 8 minutes ?

Step-by-step explanation:

Let x be the random variable representing the times a fire department takes to arrive at the scene of an emergency. Since the population mean and population standard deviation are known, we would apply the formula,

z = (x - µ)/σ

Where

x = sample mean

µ = population mean

σ = standard deviation

From the information given,

µ = 6 minutes

σ = 1 minute

the probability that fire department arrives at the scene in case of an emergency between 4 minutes and 8 minutes is expressed as

P(4 ≤ x ≤ 8)

For x = 4,

z = (4 - 6)/1 = - 2

Looking at the normal distribution table, the probability corresponding to the z score is 0.023

For x = 8

z = (8 - 6)/1 = 2

Looking at the normal distribution table, the probability corresponding to the z score is 0.98

Therefore,

P(4 ≤ x ≤ 8) = 0.98 - 0.23 = 0.75

The percent of emergencies that the fire department arrive at the scene in between 4 minutes and 8 minutes is

0.75 × 100 = 75%

y=3n + 1

step-by-step explanation:

this is wrong because it says the second number is one less and i added one instead

answer:

it is general formula that is used to write value to its excet position

a11 a12 a13

a21 a22 a23

it is the example of order 2 by 3 matrix in this

a11 means value occur in 1 st row 1st column

a12 means value occurs in 1st row 2nd column

a13 means value occur in 1st row and 3rd column

a21 means value occurs in 2nd row and 1st column

a22 means value occurs in 2nd row and in 2nd column

a23 means value occurs in 2nd row and in 3rd column