If cos 0 = 0.3846 where 3pi/2 is less than 0 is less than 2pi, what is the approximate value of sin 0?

-0.9231

Step-by-step explanation:

Given cos theta = 0.3846 within the range 3π/2<theta<2π

Costheta = 0.3846

Theta = arccos(0.3846)

Theta = 67.38°

Since 67.38° didn't fall within the range of theta, we will locate our theta using the quadrant.

Since cos is positive in the 4th quadrant,

Theta = 360-67.38°

Theta = 292.62°

Sin(theta) = sin(292.62°)

= -0.9231

probably 12 feet tops

step-by-step explanation:

no solution

step-by-step explanation:

there is not enough information in the problem to solve.