Students arrive randomly at the help desk of the computer lab. There is only one service agent, and the time required for inquiry varies from student to student. Arrival rates have been found to follow the Poisson distribution, and the service times follow the negative exponential distribution. The average arrival rate is 12 students per hour, and the average service rate is 20 students per hour. On average, how long does it take to service each student?

It takes on average 3 minutes to service each student.

Step-by-step explanation:

In queueing problem, an M/M/1 queue model is an arrangement with a single queue, where arrivals at the queue are approximated by a Poisson distribution with mean λ and the service times follows an exponential distribution with mean μ.  

The mean number of arrivals in this system is given by:  

Here the variable ρ is defined as:

From the average number of arrivals in the system, we can calculate the average number of arrivals in the queue by subtracting the average number of arrivals in service.

That is,

The information provided is:

The average number of arrivals of customers is, λ = 12 students/hour.

The average service rate of a single server is, μ = 20 students/hour.

The average of an exponential distribution is:

Compute the average time it takes to service one student as follows:

Thus, it takes on average 3 minutes to service each student.

yes, gavin is right.

step-by-step explanation:

gavin is correct. 

this problem is about converting 9% per year to how many percent per quarter. the rate is still the same. it only differed in the time period. so, through dimensional analysis,

9% per year  × (1 year / 4 quarters) = 2.25% per quarter

if he was asked to convert 9% per year to how many percent per quarter  compounded quarterly, then you will not simply divide by four. this is because compounding is not linear.

hope this , have a good day. c;

139 divided by a number

step-by-step explanation: