Consider the rectangle below. Its area is 8a^2+41ab+5b^2 and its length is
3a+15b. Find...
Mathematics, 05.05.2020 06:06 wsdafvbhjkl
Consider the rectangle below. Its area is 8a^2+41ab+5b^2 and its length is
3a+15b. Find its width w, in terms of a and b, by dividing its area by its length.
Answers: 2
Mathematics, 21.06.2019 23:40
Cos^2x+cos^2(120°+x)+cos^2(120°-x)i need this asap. pls me
Answers: 1
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