Let m=x^2.
Which equation is equivalent to (x^2-5)^2-3x^2+15=-2.

Step-by-step explanation:

We can go simplify the equation by simplifying the first polynomial:

Then, we can substitute that in the original equation:

Now, we can substitute m for every x^2.

Knowing that x^4 = x^2 * x^2, we can write this as m^2:

x= -3 and

step-by-step explanation:

to find the roots of a cubic, use division or factoring to find the factors then set equal to 0. as this is a difference of cubes, it factors into

where a is the cube root of .

here   this is 27 and the cube root of 27 is 3. so we write using the form:

.

set each factor to 0 and solve for x.

x-3=0

x=3

the quadratic expression does not factor and must be solved using the quadratic formula.

where a = 1, b=3, and c=9

this cubic has two complex roots.

where is abdul's work? don't see that anywhere posted : /

step-by-step explanation: