If a circle has a radius of \sqrt{13}

and is centered at (9, -3), what is the equation of this circle?

(x-9)^2 + (y+3)^2 = 13

Step-by-step explanation:

The equation of a circle can be written as

(x-h)^2 + (y-k)^2 = r^2

Where (h,k) is the center and r is the radius

(x-9)^2 + (y--3)^2 = (sqrt(13))^2

(x-9)^2 + (y+3)^2 = 13

congruent segments

step-by-step explanation:

a

step-by-step explanation: