Divide (-2x-3+8x^2) by (1 + 4x)

Which value is not a solution of 8x^3 – 1 = 0

Consider this equation. |y + 6| = 2 what can be concluded of the equation? check all that apply. there will be one solution. there will be two solutions. the solution to –(y + 6) = 2 will be also be a solution to the given absolute value equation. the solution(s) will be the number(s) on the number line 2 units away from –6. the value of y must be positive since the variable is inside absolute value signs.

If the class creates a histogram of the data in table, how many students are in the range 12cm to 13.9 cm