Figure ABCD is a parallelogram.
Which sequence could be used to prove that AD = BC?
First prove ABC is congruent to ACDA, and then state
AD and BC are corresponding sides of the triangles.
First prove A ABC is similar to ACDA, and then state AD
and BC are opposite sides of the parallelograms.
First prove OABCD is congruent to OCDAB, and then
state AD and BC are corresponding sides of two
parallelograms.
First prove OABCD is similar to OCDAB, and then state
AD and BC are opposite sides of the parallelograms.

ok

step-by-step explanation:

step-by-step explanation:

first, eliminate the parenthesis:

3

x

+

2

−

4

x

second, group like terms:

3

x

−

4

x

+

2

third, combine like terms:

(

3

−

4

)

x

+

2

→

−

1

x

+

2

→

−

x

+

2

- "runner b is moving at a slower rate."

- "the graphs shown are graphs of distance(km) against time(min).

the slopes of this graphs are are given by:

slope = (change in y)/(change in x)

= (change in distance)/(change in time)

this is the formula for finding the speed. so, the slope of these graphs represent the speed of the runner.

taking each division in the graph to represent 1 on both axis:

runner a ⇒ speed = (2-0)/(1-0)

= 2/1

= 2 km/min

runner b ⇒ speed = (3-0)/(3-0)

= 3/3

= 1 km/min

this shows that   runner b is moving at a slower rate."