A plane leaves the airport and flies 73 km on a bearing S30°E . It then heads due north until it is due east of the airport. How far, in km, from the airport is the plane?

check above link.

graphically?   well, you graph them both, the solutions is where they both intersect each other, since there are two solutions, meaning they will meet twice, or namely the linear will run into the quadratic curve twice, and where they meet, those x,y coordinates are the solutions to the system.

the answer is c: divide the arc's degree measure by 360°, then multiply by the circumference of the circle.

80° is the measure of gh

step-by-step explanation:

circle f is congruent to circle j

we have two circle with center f and j.

both circles are congruent. the radius of the circle would be equal.

see the attachment for the circle.

we are given ∠efd ≅ ∠gjh

therefore, arc (ed) = arc (gh)     (∴ circle f is congruent to circle j)

but ∠dfe=80°=arc (ed)

therefore, arc (gh) = 80°

thus, 80° is the measure of gh

well, because the $0.25 is an added cost depending on how many minutes, the answer would be y = 30 + 0.25x.