A regular triangular pyramid has a base and lateral faces that are congruent equilateral triangles. It has a lateral surface area of 72 square centimeters. What is the surface area of the regular triangular pyramid?

Here's your answer.

57 cm^2 is equal to the lateral surface area, or the three sides in this case.

57/3= 19 cm^2 per side. Because the base is equal to the area of the side, this is the base area.

19+57= 76 cm^2 for sides+ base (total surface area)

So, Your best answer will be is 76 cm^2.

Good Luck!~

tip $2.90

total $17.40