The sequence that proves shape I is similar to shape II when applied to shape I is a reflection across the x-axisy-axis, followed by a translation 4567 units right and 2345 units down, and then a dilation by a scale factor of

a. X-axis

b. 6

c. 2

d.2

answer: 48

just remember to use pemdas:

parentheses

expressions

multiplication

division

addition

subtraction

step-by-step explanation:

y = | -2(-2) |     →     y = | 4 |     →     y = 4       ⇒   (-2, 4)

y = | -2(-1) |     →     y = | 2 |     →       y =   2       ⇒   (-1, 2)    

y = | -2(0) |     →     y = | 0 |     →       y = 0         ⇒   (0, 0)

y = | -2(1) |   c →     y = | -2 |     →     y =   2         ⇒   (1, 2)    

y = | -2(2) |     →     y = | - 4 |     →     y =   4         ⇒   (2, 4)