In ΔJKL, k = 22 cm, ∠L=23° and ∠J=26°. Find the length of j, to the nearest 10th of a centimeter.

We have been given that in ΔJKL, k = 22 cm, ∠L=23° and ∠J=26°. We are asked to find the length of j to the nearest tenth of a centimeter.

We will use law of sines to solve for side j.

, where, a, b and c are opposite sides to angles A, B and C respectively.

We need to find measure of angle K to apply law of sine to our given problem.

Using angle sum property, we will get:

Upon rounding to nearest tenth, we will get:

Therefore, the length of j is approximately 12.8 cm.

7 ft 6 in means 7 1/2, because 6 in is 1/2 of a foot. 7 ft 8 in means 7 2/3 because 8 in is 2/3 of a foot. 23/3 = 7 2/3. 15/2 = 7 1/2.

23/3   *   15/2   = 57 1/2

step-by-step explanation: