You and some friends went to a haunted house on Halloween. The mummy scared one friend so much that she jumped into the air! The equation h= 4t(2)+ 2t models her jump where h is her jumps height in feet t seconds after the mummy scares her. Where did she reach her maximum.

Step-by-step explanation:

The question is not properly structured and the equation is also incorrect. Here is the correct question.

You and some friends went to a haunted house on Halloween. The mummy scared one friend so much that she jumped into the air! The equation h= -4t²+ 2t models her jump where h is her jumps height in feet t seconds after the mummy scares her. When did she reach her maximum.

Give the equation h= -4t²+ 2t that models my friend jump where h is her jumps height in feet t seconds, At maximum height, her velocity will be zero i.e

Vmax = 0m/s

Velocity is the rate of change in distance of a body i.e V = dh/dt

Given  h= -4t²+ 2t

V = dh/dt = -8t+2

Since v = 0m/s

0 = -8t+2

-8t = -2

t = -2/-8

t = 0.25 secs

She reaches her maximum height after 0.25 seconds

y=mx+b

step-by-step explanation:

m slope

b y-intercept