What is the radius of a sphere with a volume of 872 ft', to the nearest tenth of a foot?

5.9 ft

Step-by-step explanation:

The volume of a sphere is given by

V = 4/3 pi r^3

872 = 4/3 (3.14) r^3

872 =4.186666666 r^3

Divide each side by 4.1866666 on each side

872 / 4.186666666 = r^3

208.2802548 = r^3

Take the cube root of each side

(208.2802548)^(1/3) = r^3^(1/3)

5.927652012 = r

Rounding to the nearest tenth

5.9 ft

5.93 ft rounded to the nearest tenth is 5.9 ft

Step-by-step explanation:

Please mark me brainllest.

its b

step-by-step explanation:

6^2 or 36

step-by-step explanation:

6000n

6×1000n

6×10^3 n

so we need 6n need to be a perfect cube

so n has to be 6^2 so that 6n is 6^3

what i'm saying is if you let n be 6^2 you have 6^3×10^3 or 60^3 which is a perfect cube