A diameter of a circle has endpoints p(-10, -2) and q(4, 6)
a. Find the center of the circle
b. Find the radius. If your answer is not an integer, express it in radical form
c. Write an equation for the circle

A diameter of a circle has endpoints p(-10, -2) and q(4, 6).

a,  The center of circle is the midpoint of diameter:

O = ((px + qx)/2, (py + qy)/2) = ((-10 + 4)/2, (-2 + 6)/2) = (-3, 2)

b, Radius = Oq

                = sqrt((Ox - qx)^2 + (Oy - qy)^2)

                = sqrt((-3 - 4)^2 + (2 - 6)^2)

                = sqrt(7^2 + 4^2)

                = sqrt(65)

Hope this helps!

:)

A) (-3,2)

B) sqrt(65)

C) (x + 3)² + (y - 2)² = 65

Step-by-step explanation:

Centre: midpoint of the diameter

(-10+4)/2, (-2+6)/2

(-3,2)

Radius = diameter/2

sqrt[(6--2)² + (4--10)²]/2

sqrt(65)

Equation:

(x - -3)² + (y - 2)² = (sqrt(65))²

(x + 3)² + (y - 2)² = 65

12m

step-by-step explanation:

square root means have of a number so have of 3 is 1.5 then multiply it by 8 and you get your answer!

sorry i just need to anwers this to get points

step-by-step explanation: