How can Ari simplify the following expression?
5
.4
a-3
2+
a-3
Write the numerator and denominator with a common denominator. Then divide the numerator by the denominator. To do
this, multiply the numerator by the reciprocal of the denominator.
Write the numerator and denominator with a common denominator. Then divide the numerator by the denominator. Tamiya
this, multiply the numerators and multiply the denominators.
Divide the numerator and the denominator by a - 3. Then divide the numerator by the denominator.
Divide the numerator and the denominator by a - 3. Then simplify the numerator and simplify the denominator.

On a coordinate grid, point p is at (4, 3) and point r is at (−2, −5). points q and s are a reflection of both points across the x-axis. what are the coordinates of q and s? q(−4, 3), s(2, −5) q(4, −3), s(−2, 5) q(−4, −3), s(2, 5) q(−4, 3), s(−2, 5) ; -; i can't figure it out, if someone can me with the answer,that would be nice

1- is the product of two rational numbers irrational or rational? first, make a hypothesis by multiplying two rational numbers. then, use variables such as x=a/b and y=c/d and the closure property of integers to prove your hypothesis. 2- what do you think the product of a nonzero rational number and an irrational number is? is it rational or irrational? make use of variables, the closure property of integers, and possibly a proof by contradiction to prove your hypothesis. 3- why do we have to specify that the rational number must be nonzero when we determine what the product of a nonzero rational number and an irrational number is? if the rational number were 0, would it give us the same result we found in part b?

(c) the diagram shows the first three shapes of a matchsticks arrangement.first shape = 3second shape = 5third shape = 7given m represents the number of matchstick used to arrange the n'th shape.(i) write a formula to represent the relation between m and n. express m as the subjectof the formula.(ii) 19 matchsticks are used to make the p'th shape. find the value of p.