If each sandwich consists of one type of bread, one type of cheese, and one type of meat, which best represents four of his possible sandwich choices?

WST, WGF,  WSC, WGT

Step-by-step explanation:

As each sandwich consists of one type of bread, one type of cheese, and one type of meat, there must be one letter out of W, I and B. There must be one cheese and there must be one letter out of G and S. There must be one meat and there must be one letter out of C, T, F and H.

The possible combinations must include three letters. Thus  WSTWG, WS, WC, WTWGT, WSHWGSC and WGSF  could not be the right choices.

The possible combinations are WST in which W is for wheat bread, S is for sliced cheese and T is for turkey meat.

WGF,  in which W is for wheat bread, G is for grated cheese and F is for fish meat.

WSC, in which W is for wheat bread, G is for grated cheese and F is for fish meat.

WGT, in which W is for wheat bread, G is for grated cheese and T is for turkey meat.

i am currently in the exact same situation rn. algebra2/adv algebra is killing

step-by-step explanation:

answer: b. f(x) = (x + 2)^3 (x^2 - 7x + 3)^4

step-by-step explanation:

polynomials always have as many roots as their order. this is a 4th order polynomial- hence 4 roots!

complex roots of polynomials always come in pairs. the quadratic equation has the "+/-" in that will alwaysgenerate m+ni amd m-ni, so 7-2i must be a root of this polynomial equation.

the order of the numerator and denominator are both 2. so the horizontal asymptote is y=a2/b2 =7

verticle asymptotes are the forbidden x-values. f(x) becomes undefined at x=-3 because this value will cause a zero denominator.

a graph of r(x) will have vertical asymptotes at ±1 because these values will make the denominator zero. so the domain of the function cannot include ±1.

you 're wlecome! : )

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