The graph of which function has an axis of symmetry at x=-1/4?

2x^2 + 1x + C

Step-by-step explanation:

The three coefficients of a quadratic function are a, b and c, where a is the coefficient of the x^2 term.

The equation of the axis of symmetry is

          -b

x =    and   here we are told that this x is -1/4.

          2a

From this info we can assume that a = 2 and that b = 1

and so the function is likely 2x^2 + 1x + C, where C is a constant.  Doesn't matter what C is in this case.

explanation:

previous steps have made pa≅ pb ≅ st ≅ su. setting the compass width to ab allows you to make tu the same length. then δstu ≅ δpab by the sss congruence postulate, and ∠p ≅ ∠s by the reason cpctc.

2

step-by-step explanation: